The Balmer series in the hydrogen spectrum corresponds to the transition from n1 = 2 to n2 = 3, 4,.......... This series lies in the visible region. Calculate the wave number of line associated with - Chemistry | Shaalaa.com
The Balmer series in the hydrogen spectrum corresponds to the tran…
Sep 16, 2024
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SOLVED:Use the Balmer equation to calculate the wavelength in nanometers of the spectral line for hydrogen when n=6 What is the energy in kilojoules per mole of the radiation corresponding to this line?
SOLVED:Use the Balmer equation to calculate the wavelength in nano…
Nov 12, 2019
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Derive the Balmer equation from equation (8.6)... | Filo
Derive the Balmer equation from equation (8.6)... | Filo
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Use the Balmer equation (8.4) to determine (a) the frequency, in s^-1, of the radiation corresponding to n=5 (b) the wavelength, in nanometers, of the line in the Balmer series corresponding to n=7 (c) the value of n corresponding to the Balmer series line at 380 nm | Numerade
Use the Balmer equation (8.4) to determine (a) the frequency, in s^ …
Oct 24, 2020
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The Balmer equation can be extended beyond the visible portion of the electromagnetic spectrum to include lines in the ultraviolet. What is the wavelength in nanometers and energy in kJ / mol of ultraviolet light in the Balmer series corresponding to a value of n=7 ? | Numerade
The Balmer equation can be extended beyond the visible porti…
2 months ago
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SOLVED: A transition in the Balmer series for hydrogen has an observed wavelength of 274 nm. What is the change in energy (ΔE) of a transition in kJ? (Put your answer in exponential notation and 3 significant figures) photon c=νλ and ΔE = hν, where c = 2.998x10^8 m/s and h = 6.626x10^-34 J·s. NOTE: To type your exponential number in correctly, Avogadro's number would be entered as 6.02e23 and Planck's constant (h) would be typed in as 6.63e-34.
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